(-3x^3y^2)^-1/(w^2z^4)^3

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Solution for (-3x^3y^2)^-1/(w^2z^4)^3 equation: 


D( x )

(w^2*z^4)^3 = 0

-3*x^3*y^2 = 0

(w^2*z^4)^3 = 0

(w^2*z^4)^3 = 0

w^6*z^12 = 0

x naleu017Cy do R

-3*x^3*y^2 = 0

-3*x^3*y^2 = 0

-3*x^3*y^2 = 0 // : -3*y^2

x^3 = 0

x = 0

x belongs to the empty set

((-3*x^3*y^2)^-1)/((w^2*z^4)^3) = 0

x belongs to the empty set

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